How do you solve the system of equations $4x + 3y = 13$ and $6x + 2y = 17$ ?

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Answer 1 · 2017-08-13T13:24:06

see below

$4x+3y=13$ , $6x+2y=17$

Multiply equation $(2)$ by $3/2$ ,

$=>9x+3y=51/2$

Subtract equation $(1)$ from this obtained equation,

$=>5x=25/2$

$=>x=5/2$

Now anyone can easily solve for $y$ ,

$y=(17-6x)/2=(17-15)/2=1$

So,

$x=5/2$ , $y=1$

How do you solve the system of equations 4x + 3y = 134x + 3y = 13 and 6x + 2y = 176x + 2y = 17?