How do you solve the system of equations #4x + 3y = 13# and #6x + 2y = 17#?

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Answer 1 · 2017-08-13T13:24:06

see below

#4x+3y=13#, #6x+2y=17#

Multiply equation #(2)# by #3/2#,

#=>9x+3y=51/2#

Subtract equation #(1)# from this obtained equation,

#=>5x=25/2#

#=>x=5/2#

Now anyone can easily solve for #y#,

#y=(17-6x)/2=(17-15)/2=1#

So,

#x=5/2#, #y=1#