How do you divide $4 x^{3} + 6 x^{2} - 23 x - 15 \div (3 + x)$ $4x ^ { 3} + 6x ^ { 2} - 23x - 15\div ( 3+ x )$ ?

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How do you divide $4 x^{3} + 6 x^{2} - 23 x - 15 \div (3 + x)$ $4x ^ { 3} + 6x ^ { 2} - 23x - 15\div ( 3+ x )$ ?

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Answer 1 · 2017-08-13T02:19:37

I a man assuming you mean to include brackets around the first four terms!

Answer 2 · 2017-08-13T20:24:46

$4 x^{2} - 6 x - 5$ $4x^2-6x-5$

Explanation:

$one way is to use the divisor as a factor in the numerator$ $"one way is to use the divisor as a factor in the numerator"$

$consider the numerator$ $"consider the numerator"$

$4 x^{2} (x + 3) - 12 x^{2} + 6 x^{2} - 23 x - 15$ $color(red)(4x^2)(x+3)color(magenta)(-12x^2)+6x^2-23x-15$

$= 4 x^{2} (x + 3) - 6 x (x + 3) + 18 x - 23 x - 15$ $=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(magenta)(+18x)-23x-15$

$= 4 x^{2} (x + 3) - 6 x (x + 3) - 5 (x + 3) + 15 - 15$ $=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(red)(-5)(x+3)color(magenta)(+15)-15$

$= 4 x^{2} (x + 3) - 6 x (x + 3) - 5 (x + 3) + 0$ $=color(red)(4x^2)(x+3)color(red)(-6x)(x+3)color(red)(-5)(x+3)+0$

$\Rightarrow \frac{4 x^{3} + 6 x^{2} - 23 x - 15}{x + 3} = 4 x^{2} - 6 x - 5$ $rArr(4x^3+6x^2-23x-15)/(x+3)=color(red)(4x^2-6x-5)$

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How do you divide $4 x^{3} + 6 x^{2} - 23 x - 15 \div (3 + x)$ $4x ^ { 3} + 6x ^ { 2} - 23x - 15\div ( 3+ x )$ ?

2 Answers

Explanation:

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How do you divide $4 x^{3} + 6 x^{2} - 23 x - 15 \div (3 + x)$ $4x ^ { 3} + 6x ^ { 2} - 23x - 15\div ( 3+ x )$ ?