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Answer 1 · 2017-08-06T10:38:09

Around $107, 543$ $107,543$ $k m$ $km$ / $h o u r$ $hour$

Earth Orbits The Sun 365 days a year.

$S p e e d = \frac{D i s tan c e}{T i m e}$ $Speed=(Distance)/(Time)$ .

$D i s tan c e = 2 π r$ $Distance=2pir$

$T i m e = 365 d a y s \cdot 24 h r = 8760 h r s$ $Time=365days*24hr=8760hrs$

$r = a u = 1.496 \cdot 10^{8} k m$ $r=au=1.496*10^8km$ *

Lets take $a u$ $au$ as $1.5 \cdot 10^{8} k m$ $1.5*10^8km$

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Applying formula,

$S p e e d = \frac{2 \cdot π \cdot 1.5 \cdot 10^{8}}{8760}$ $Speed=(2*pi*1.5*10^8)/8760$

Lets take $π$ $pi$ as $3.14$ $3.14$ ,

$S p e e d = \frac{2 \cdot 3.14 \cdot 1.5 \cdot 10^{8}}{8760} = \frac{942, 000, 000}{8760} =$ $Speed=(2*3.14*1.5*10^8)/8760=(942,000,000)/8760=$

$107, 543 (\approx)$ $107,543(approx)$ $k m$ $km$ $/ h r$ $/hr$ .

au= Astronomical unit - is the average distance between the sun and earth.*