How do you solve #\tan ( 2\theta ) = 1#?

1 Answer
Kevin B. · Shwetank Mauria
Aug 6, 2017

#theta = n*pi/2 + pi/8#, where #n# is an integer

Explanation:

We start with #tan(2theta)=1#

So tangent of what angle equals #1#? Tangent of #pi/4# equals #1# and tangent of #(5pi)/4# equals #1# and tangent #(9pi)/4#, and by extension tangent of any #n*pi + pi/4 = 1#, where #n# is an integer

Therefore our angle #2theta= n*pi + pi/4#

So #theta = n*pi/2 + pi/8#

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