Question #6fac0

1 Answer
Jul 31, 2017

z = 0 and #i^(1/3)#

Explanation:

#z^4 +iz = 0# can be solved by factoring.
first you can factor out a z
#z(z^3+i) = 0#
second you find the zeros by finding the values where z = 0.
Since z is multiplied by the term #(z^3+i)# we know the answer will be true because when z = 0 the other 0 is when #z^3# = -i thus z = cubed root of i which can be written as #i ^(1/3)#

z = 0 and #i^(1/3)#