Question #9d584

1 Answer
tcw1
Jul 31, 2017

#r=atanΘ/cosΘ+bsecΘ+c# where #y=ax^2+bx+c#

Explanation:

It depends on the original parabola. To name one, we will use #y=-x^2+10x#, which looks like this:Google To convert from rectangular to polar, we use the equations, #x=rcosΘ# and #y=rsinΘ#
Substitute x and y for their respective values:
#r sinΘ=-(r cosΘ)^2+10r cos Θ#
Solve for r:
#r sinΘ=-r^2cos^2Θ+10rcosΘ#
#-sinΘ+10cosΘ=rcos^2Θ#
#r=-tanΘ/cosΘ+10secΘ#

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