Question #054f6

1 Answer
Cri007
Jul 30, 2017

You cannot factor this.

Explanation:

We are actually unable to factor this equation (unless you use the quadratic formula). This is because #65=13\cdot5#, so there is no way to create a coefficient of #4# for the #x# term (#13-5=8,-13+5=-8#)

However, let's just find the roots.

Using the quadratic formula,

#x=(-4\pmsqrt(4^2-(4)(1)(-65)))/2=(-4\pmsqrt(16+260))/2=(-4\pmsqrt(276))/2=(-4\pm2sqrt(69))/2=-2pmsqrt(69)#

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