How do you identify the axis of symmetry and vertex of $f(x) = -x^2-2x-1$ ?

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Answer 1 · 2017-07-27T21:41:34

Vertex:
$(-1, 0)$

Axis of symmetry:
$x = -1$

$f(x) = ax^2 + bx + c$

Vertex:
$(-b/(2a), f(-b/(2a)))$

Axis of symmetry:
$x = -b/(2a)$

How do you identify the axis of symmetry and vertex of f(x) = -x^2-2x-1f(x) = -x^2-2x-1?