How do you find the area of triangle ABC given a=2, b=3, c=4?

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Answer 1 · 2017-07-23T09:42:40

The area is #=2.9u^2#

We apply Heron's formula

#area =sqrt(s(s-a)(s-b)(s-c))#

Where

#s=(a+b+c)/2#

Here,

#a=2#

#b=3#

#c=4#

Therefore,

#s=(2+3+4)/2=9/2=4.5#

So,

# area = sqrt (4.5*(4.5-2) * (4.5-3) * (4.5-4) ) #

#=sqrt8.3475#

#=2.9u^2#

Where #u#, represents the units in this case.