How do you multiply and simplify $\frac{- 8 b^{4} z^{6} \cdot 3 b^{2} z^{2}}{- 6 b^{14} z^{9}}$ $\frac { - 8b ^ { 4} z ^ { 6} \cdot 3b ^ { 2} z ^ { 2} } { - 6b ^ { 14} z ^ { 9} }$ ?

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Answer 1 · 2017-07-22T21:18:38

Simple. Just use simple order of operations and the rule of the exponents to figure out and simplify the answer.

$\frac{- 8 b^{4} z^{6} \cdot 3 b^{2} z^{2}}{- 6 b^{14} z^{9}}$ $(-8b^4z^6*3b^2z^2)/(-6b^14z^9)$

Simplify the numerator first.

$= \frac{- 24 b^{6} z^{8}}{- 6 b^{14} z^{9}}$ $=(-24b^6z^8)/(-6b^14z^9)$

Now simplify with the corresponding terms and variables.

$= \frac{4}{b^{8} z}$ $=4/(b^8z)$

How do you multiply and simplify \frac { - 8b ^ { 4} z ^ { 6} \cdot 3b ^ { 2} z ^ { 2} } { - 6b ^ { 14} z ^ { 9} }−8b4z6⋅3b2z2−6b14z9\frac { - 8b ^ { 4} z ^ { 6} \cdot 3b ^ { 2} z ^ { 2} } { - 6b ^ { 14} z ^ { 9} }?