How do you solve the system of equations $9 x = - 2 y + 129$ $9x=-2y+129$ and $y = - x + 12$ $y=-x+12$ ?

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How do you solve the system of equations $9 x = - 2 y + 129$ $9x=-2y+129$ and $y = - x + 12$ $y=-x+12$ ?

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Answer 1 · 2017-07-22T18:33:38

$x = 15, y = - 3$ $x=15, y=-3$

Explanation:

$9 x = - 2 y + 129$ $9x=-2y+129$ -------- $(1)$ $(1)$
$y = - x + 12$ $y=-x+12$ ------------- $(2)$ $(2)$

Substitude $(2)$ $(2)$ into $(1)$ $(1)$
$\Rightarrow$ $rArr$ $9 x = - 2 (- x + 12) + 129$ $9x=-2(-x+12)+129$
$\Rightarrow$ $rArr$ $9 x = 2 x - 24 + 129$ $9x=2x-24+129$
$\Rightarrow$ $rArr$ $7 x = 105$ $7x=105$
$\Rightarrow$ $rArr$ $x = \frac{105}{7}$ $x=105/7$
$\Rightarrow$ $rArr$ $x = 15$ $x=15$

Substitude $x = 15$ $x=15$ into $(2)$ $(2)$
$\Rightarrow$ $rArr$ $y = - 15 + 12$ $y=-15+12$
$\Rightarrow$ $rArr$ $y = - 3$ $y=-3$

$:. x=15, y=-3$

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How do you solve the system of equations $9 x = - 2 y + 129$ $9x=-2y+129$ and $y = - x + 12$ $y=-x+12$ ?

1 Answer

Explanation:

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How do you solve the system of equations $9 x = - 2 y + 129$ $9x=-2y+129$ and $y = - x + 12$ $y=-x+12$ ?