How do you simplify $\frac{{(x^{3} y^{4})}^{2}}{{(x^{- 4} y^{- 4})}^{2}}$ $\frac { ( x ^ { 3} y ^ { 4} ) ^ { 2} } { ( x ^ { - 4} y ^ { - 4} ) ^ { 2} }$ ?

Question

888 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-22T16:25:08

Use the order of operations and distribution of exponents to figure out this answer.

$\frac{{(x^{3} y^{4})}^{2}}{{(x^{- 4} y^{- 4})}^{2}}$ $(x^3y^4)^2/(x^-4y^-4)^2$

Distribute the square exponent to the other terms.

$= \frac{x^{9} y^{8}}{x^{- 8} y^{- 8}}$ $=(x^9y^8)/(x^-8y^-8)$

Use the negative property of exponents and add the corresponding terms to find out the answer.

$= x^{17} y^{16}$ $=x^17y^16$

How do you simplify (x3y4)2(x−4y−4)2\frac { ( x ^ { 3} y ^ { 4} ) ^ { 2} } { ( x ^ { - 4} y ^ { - 4} ) ^ { 2} }?