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Question #03a5b

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Jul 20, 2017

$P = 4184 W$ $P=4184W$

Explanation:

So let's say that the ice was at $0^{o} C$ $0""^oC$ to start with , and the man gets it to $1^{o} C$ $1""^oC$ .

So $1 k c a l = 4184 J$ $1kcal=4184J$ is equal to the power needed for $1 g$ $1g$ of water to get hotter by $1^{o} C$ $1""^oC$ .

The energy that was put in the ice therefore was :

$E = 60 \cdot 4184 J = 251040 J$ $E=60*4184J=251040J$

The power is then :

$P=E/(Δt)=251040/60=4184W$

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