How do you multiply and simplify $\frac { 4a ^ { 2} b } { b ^ { 2} c } \cdot \frac { 6b ^ { 4} c ^ { 2} } { 8a b ^ { 2} }$ ?

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Answer 1 · 2017-07-20T07:34:12

$3abc$

There are several ways to multiply and simplify this expression... Hopefully you'll understand how I do it...

Step 1) Simplify each fraction as a whole fraction

$(4a^2b)/(b^2c)*(6b^4c^2)/(8ab^2)$

$=(4a^2)/(bc)*(3b^2c^2)/(4a)$

Step 2) Cross multiply

$=a/(bc)*3b^2c^2$

$=a*3bc$

Step 3) Multiply

$=3abc$

How do you multiply and simplify \frac { 4a ^ { 2} b } { b ^ { 2} c } \cdot \frac { 6b ^ { 4} c ^ { 2} } { 8a b ^ { 2} }\frac { 4a ^ { 2} b } { b ^ { 2} c } \cdot \frac { 6b ^ { 4} c ^ { 2} } { 8a b ^ { 2} }?