Question #cdc8b

1 Answer
Jim G.
Jul 19, 2017

#0.0005" to 4 dec. places"#

Explanation:

#"there are 13 spades in a standard deck of cards"#

#P("first spade")=13/52=1/4#

#"since there is no replacement"#

#"for the next selection there will be 51 cards and 12 spades"#

#P("second spade")=12/51=4/17#

#"for the next selection there are 50 cards and 11 spades"#

#P("third spade")=11/50#

#"for next selection there are 49 cards and 10 spades"#

#P("fourth spade")=10/49#

#"final selection there are 48 cards and 9 spades"#

#P("fifth spade")=9/48=3/16#

#"the probability of getting 5 spades is calculated by"#
#"multiplying the 5 probabilities together"#

#P("5 spades")=1/4xx4/17xx11/50xx10/49xx3/16#

#color(white)(xxxxxxxx)~~0.0005" to 4 dec. places"#

Related questions
Impact of this question
635 views around the world
You can reuse this answer
Creative Commons License