How do you solve $64 = 6 (6 - m) - m$ $64= 6( 6- m ) - m$ ?

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Answer 1 · 2017-07-19T16:06:32

$m = - 4$ $m = -4$

$64 = 6 (6 - m) - m$ $64 = 6(6 - m) - m$

$64 = (6 \times 6) - 6 m - m$ $64 = (6×6) - 6m - m$

$64 = 36 - 6 m - m$ $64 = 36 - 6m - m$

$64 = 36 - 7 m$ $64 = 36 - 7m$

$7 m = 36 - 64$ $7m = 36 - 64$

$7 m = - 28$ $7m = -28$

$m = - 4$ $m = -4$

Answer 2 · 2017-07-19T16:06:54

$m = - 4$ $m=-4$

$64 = 6 (6 - m) - m \Leftrightarrow 64 = 36 - 6 m - m \Leftrightarrow 28 = - 7 m \Leftrightarrow$ $64=6(6-m)-m iff 64=36-6m-m iff 28=-7m iff$

$m = - \frac{28}{7} = - 4$ $m=-28/7=-4$

How do you solve 64=6(6−m)−m64= 6( 6- m ) - m?