How do you solve #64= 6( 6- m ) - m#?

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Answer 1 · 2017-07-19T16:06:32

#m = -4#

#64 = 6(6 - m) - m#

#64 = (6×6) - 6m - m#

#64 = 36 - 6m - m#

#64 = 36 - 7m#

#7m = 36 - 64#

#7m = -28#

#m = -4#

Answer 2 · 2017-07-19T16:06:54

#m=-4#

#64=6(6-m)-m iff 64=36-6m-m iff 28=-7m iff#

#m=-28/7=-4#