At room temperature, an oxygen molecule, with mass of #5.31 x 10^-26 kg#, typically has a KE of about #6.21 x 10-21# J. How fast is the molecule moving?

1 Answer
IDKwhatName
Jul 18, 2017

#484ms^(-1)#

Explanation:

#E_k=(mv^2)/2=6.21*10^(-21)J#

#6.21*10^(-21)=(5.31*10^(-26)v^2)/2#

#v=sqrt((2(6.21*10^(-21)))/(5.31*10^(-26)))=483.630339~~484ms^(-1)#

Related questions
See all questions in Energy
Impact of this question
20296 views around the world
You can reuse this answer
Creative Commons License