How do you solve #8x + ( - 65) > - 5x + ( 26)#?

1 Answer
Kilwee
Jul 16, 2017

Isolate x and solve for it, as done if the > were a = . Result is #x>7#

Explanation:

You can solve inequalities similarly to how you solve normal equations. In this case it would be as follows:

#8x + (-65) > -5x + (26)#
#8x - 65 > -5x + 26#

isolate #x# by adding #5x# and #65# to both sides...

#13x > 91#
#x>91/13#
#x>7#

Alternatively, if you were to isolate #x# by subtracting #8x# from both sides you would end up with a negative coefficient of #x#. When you would divide by this coefficient in the final step, you have to flip the > sign into a < sign, as follows:

#8x - 65 > -5x + 26#
#-91 > -13x#

and then the switch...
#(-91)/-13 < x#

to result in # 7 < x #, or # x > 7#, as we found above

Related questions
Impact of this question
1049 views around the world
You can reuse this answer
Creative Commons License