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How do you completely factor #x ^ { 6} - 18x ^ { 5} + 81x ^ { 4}#?

1 Answer

Jul 16, 2017

#x^4(x-9)^2#

Explanation:

If you take #x^4# out as the initial factor, you're left with:

#x^4(x^2-18x+81)#

This quadratic can further be factorised to:

#(x-9)(x-9)# which gives the answer above.

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