Question #7ba0c

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Question #7ba0c

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Answer 1 · 2017-07-09T22:16:18

$- \frac{(\sqrt{2} + \sqrt{3} + \sqrt{58}) (53 + 2 \sqrt{6})}{2785}$ $- frac{(sqrt 2 + sqrt 3 + sqrt 58)(53 + 2 sqrt 6)}{2785}$

Explanation:

$\frac{1}{\sqrt{2} + \sqrt{3} - \sqrt{58}} \cdot \frac{\sqrt{2} + \sqrt{3} + \sqrt{58}}{\sqrt{2} + \sqrt{3} + \sqrt{58}}$ $frac{1}{sqrt 2 + sqrt 3 - sqrt 58} * frac{sqrt 2 + sqrt 3 + sqrt 58}{sqrt 2 + sqrt 3 + sqrt 58}$

$= \frac{\sqrt{2} + \sqrt{3} + \sqrt{58}}{2 + 2 \sqrt{6} + 3 - 58} \cdot \frac{- 53 - 2 \sqrt{6}}{- 53 - 2 \sqrt{6}}$ $= frac{sqrt 2 + sqrt 3 + sqrt 58}{2 + 2sqrt 6 + 3 - 58} * frac{-53 - 2 sqrt 6}{-53 - 2 sqrt 6}$

$= - \frac{(\sqrt{2} + \sqrt{3} + \sqrt{58}) (53 + 2 \sqrt{6})}{53^{2} - 4 \cdot 6}$ $= - frac{(sqrt 2 + sqrt 3 + sqrt 58)(53 + 2 sqrt 6)}{53^2 - 4*6}$

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Question #7ba0c

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