How do you evaluate #15- 2+ 1\times 3+ 4#?

1 Answer
Moksha
Jun 29, 2017

The answer is 20 and see below for the procedure!

Explanation:

So for this equation, since it is the Order of the Operations, I will be using PEMDAS:

P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction

Note: For multiplication and division, do whichever one that comes first in the equation and same for addition and subtraction. :)
Now, let's start working it out!

Procedure:
Parentheses:
None

Exponents:
None

Multiplication:
#15−2+ **1×3** +4#
I made the problem bold.

#1times3=**3**#

Now the equation will be, #15−2+3+4#!

Division:
None

Now lets move on to Addition! But, wait a second, Subtraction is before Addition in the equation so we have to do Subtraction first now! Lets solve the subtraction problem in the equation, so let's solve it now!

Subtraction:
#**15-2**+3+4#
I made the problem bold.

#15-2=**13**#

The equation now is #13+3+4#!

Addition:
#**13+3+4** #13+3=16# #16+4=20#

So our final answer is #20#!
My source is my mind!

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