How do you evaluate 15- 2+ 1\times 3+ 415−2+1×3+4?

1 Answer
Moksha
Jun 29, 2017

The answer is 20 and see below for the procedure!

Explanation:

So for this equation, since it is the Order of the Operations, I will be using PEMDAS:

P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction

Note: For multiplication and division, do whichever one that comes first in the equation and same for addition and subtraction. :)
Now, let's start working it out!

Procedure:
Parentheses:
None

Exponents:
None

Multiplication:
15−2+ **1×3** +415−2+∗1×3∗+4
I made the problem bold.

1times3=**3**1×3=∗3∗

Now the equation will be, 15−2+3+415−2+3+4!

Division:
None

Now lets move on to Addition! But, wait a second, Subtraction is before Addition in the equation so we have to do Subtraction first now! Lets solve the subtraction problem in the equation, so let's solve it now!

Subtraction:
**15-2**+3+4∗15−2∗+3+4
I made the problem bold.

15-2=**13**15−2=∗13∗

The equation now is 13+3+413+3+4!

Addition:
**13+3+4** ∗13+3+4∗13+3=16 16+4=20#

So our final answer is 2020!
My source is my mind!

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