Question #9da19

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1 Answer
matt h.
Jun 28, 2017

#x= #any number

Explanation:

First, re-write #x# as # e^lnx#
This gives us: #(e^lnx)^(1/lnx)#

Then, we simplify using index laws:
#e^{1/lnx*lnx}=> e^{lnx/lnx} #
now we have simplified this to #e^{lnx/lnx}# therefore, this works for any x value that you plug in because they always cancel out to give 1 in the index.

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