How do you solve #(x - 9) ^ { 2} - 5= 16#?

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Answer 1 · 2017-06-27T16:56:38

See below.

Let's rewrite the equation:

#(x-9)(x-9)-5=16#

#x^2-9x-9x+81-5=16#

#x^2-18x+76=16#

#x^2-18x+60=0#

Now use the quadratic formula to solve for the roots.