What is the slope of the line of this equation: #9x + 8y -13 =0#?

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Answer 1 · 2017-06-24T07:31:29

#m=-9/8#

The slope of a line can be found when a linear equation is written in the form:

#y = mx + b#

Where #m# is the slope of the line.

You can get to this form, by algebraically isolating the #y#.

#9x+8y-13=0#

Add #13# to both sides:

#9x+8y=13#

Subtract #9x# from both sides:

#8y=-9x+13" "#(notice the #9x# can go in front of #13#)

Divide both sides by #8#:

#y=-9/8x+13/8#

The slope is the coefficient of the #x# term.

ANSWER: #m=-9/8#

Answer 2 · 2017-06-24T07:36:01

Slope = #-9/8#

The equation of a straight line in slope #(m)# and intercept #(c)# form is: #y=mx+c#

in this example: #9x+8y-13=0# can be written as:

#y= -9/8x+13/8#

Hence the slope of #y# is #-9/8# and the #y-#intercept is #13/8#

The graph of #y# is shown below:
graph{9x+8y-13=0 [-10, 10, -5, 5]}