How do you solve $- \frac{2 x - 6}{3} = \frac{x}{5} + 2$ $-\frac { 2x - 6} { 3} = \frac { x } { 5} + 2$ ?

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How do you solve $- \frac{2 x - 6}{3} = \frac{x}{5} + 2$ $-\frac { 2x - 6} { 3} = \frac { x } { 5} + 2$ ?

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Answer 1 · 2017-06-23T03:06:12

x = 0

Explanation:

Multiply all the terms by 15 the least common multiple.

$15 \times - \frac{2 x - 6}{3} = 15 \times (\frac{x}{5} + 2)$ $15 xx -( 2x -6)/3 = 15 xx( x/5 + 2)$ This gives

$- 10 x + 30 = 3 x + 30$ $-10x + 30 = 3x + 30$ subtract 30 from both sides

$- 10 x + 30 - 30 = 3 x + 30 - 30$ $-10x + 30 - 30 = 3x + 30 - 30$ the result is

$- 10 x = 3 x$ $- 10 x = 3x$ add 10x to both sides

$- 10 x + 10 x = 3 x + 10 x$ $-10x + 10x = 3x + 10x$ which equals

$0 = 13 x$ $0 = 13 x$ divide both sides by 13

$\frac{0}{13} = \frac{13 x}{13}$ $0/13 = (13x)/13$ the answer is

$0 = x$ $0 = x$

Answer 2 · 2017-06-23T03:07:34

Answer: $x = 0$ $x=0$

Explanation:

Solve $- \frac{2 x - 6}{3} = \frac{x}{5} + 2$ $-(2x-6)/3=x/5+2$ for $x$ $x$ .

We can start by getting rid of the fractions by multiplying everything by the least common multiple (lcm) of the denominators ( $3$ $3$ , $5$ $5$ , and $1$ $1$ ), which is $15$ $15$ .

So, we get:
$15 (- \frac{2 x - 6}{3} = \frac{x}{5} + 2)$ $15(-(2x-6)/3=x/5+2)$

$- 5 (2 x - 6) = 3 x + 30$ $-5(2x-6)=3x+30$

Simplifying, we get:
$- 10 x + 30 = 3 x + 30$ $-10x+30=3x+30$

Subtracting $30$ $30$ from both sides and adding $10 x$ $10x$ to both sides, we get:
$13 x = 0$ $13x=0$

Dividing both sides by $13$ $13$ , we get our answer:
$x = 0$ $x=0$

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How do you solve $- \frac{2 x - 6}{3} = \frac{x}{5} + 2$ $-\frac { 2x - 6} { 3} = \frac { x } { 5} + 2$ ?

2 Answers

Explanation:

Explanation:

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How do you solve -\frac { 2x - 6} { 3} = \frac { x } { 5} + 2−2x−63=x5+2-\frac { 2x - 6} { 3} = \frac { x } { 5} + 2?

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Explanation:

Explanation:

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How do you solve $- \frac{2 x - 6}{3} = \frac{x}{5} + 2$ $-\frac { 2x - 6} { 3} = \frac { x } { 5} + 2$ ?