How do you solve $-4( v + 1) = 2v - 8+ 2( 4v + 7)$ ?

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Answer 1 · 2017-06-23T01:18:39

$v=-5/7$

$-4(v+1)=2v-8+2(4v+7)$

The first step is to use the distributive property to get rid of the parentheses.

$-4(v)-4(1)=2v-8+2(4v)+2(7)$

$-4v-4=2v-8+8v+14$

Next, combine like terms.

$-4v-4=10v+6$

Your goal is to isolate $v$ , so you can do this by subtracting $10v$ on both sides.

$-14v-4=6$

Now you need to move all the constants to the other side. Add $4$ on both sides.

$-14v=10$

Last, all you have to do is divide $-14$ on both sides to completely isolate $v$ !

$v=-10/14$

Don't forget to write your fraction in simplest form.

$v=-5/7$

How do you solve -4( v + 1) = 2v - 8+ 2( 4v + 7)-4( v + 1) = 2v - 8+ 2( 4v + 7)?