How do you add #\frac { 4x } { 3x - 1} + \frac { 9} { x + 4}#?

1 Answer
Andy Y.
Jun 22, 2017

#(4x^2+43x-9)/((3x-1)(x+4))#

Explanation:

The denominators must be the same in order to add fractions.

#(4x)/(3x-1)(x+4)/(x+4)+(3x-1)/(3x-1)9/(x+4)#

#(4x^2+16x)/((3x-1)(x+4))+(27x-9)/((3x-1)(x+4))#

#(4x^2+16x+27x-9)/((3x-1)(x+4))#

#(4x^2+43x-9)/((3x-1)(x+4))#

Because the numerator does not factor (at least not to anything nicely), this completes the addition.

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