Question #b6b70

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Question #b6b70

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Answer 1 · 2017-06-22T07:43:01

The density of $N_{2}$ $N_2$ is 1.250625 g/L
or simply 1.25 g/L

Explanation:

At STP,

The molecular mass of $N_{2}$ $N_2$ is 28.014 g/mol.

The volume of $N_{2}$ $N_2$ is 22.4L.

Density of $N_{2}$ $N_2$ =Molecular mass of $N_{2}$ $N_2$ )/Volume of $N_{2}$ $N_2$

$\Rightarrow$ $rArr$ $\frac{28.014}{22.4}$ $(28.014)/(22.4)$ g/L

= 1.2506255 g/L

                                              or simply 1.25 g/L.

Answer 2 · 2017-06-22T07:47:10

First - be aware that it DOESN'T.
$\frac{28 g}{22.4 L} = 1.25 \frac{g}{L}$ $(28g)/(22.4L) = 1.25 g/L$

Explanation:

It only occupies that volume at STP, not NTP. It is unnecessary given the terms of the terms of the problem in any case.
A mole of nitrogen ( $N_{2}$ $N_2$ ) has a mass of 28 grams/mole. Density is mass per unit volume, so the density is simply:

$\frac{28 g}{22.4 L} = 1.25 \frac{g}{L}$ $(28g)/(22.4L) = 1.25 g/L$

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