How do you divide #\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }#?

1 Answer
MattC
Jun 22, 2017

Here is the answer:#((8y^19)/(x^15))#

Explanation:

First of all, expand the exponents:#((4x^8y^5)/(8x^3y^3))/((x^24y^15)/(16x^4y^32))#

Next, switch the sign and find the reciprocal of the fraction:#((4x^8y^5)/(8x^3y^3))*((16x^4y^32)/(x^24y^15))#

Multiply:#((64x^12y^37)/(8x^27y^18))#

Cancel terms to get the final answer:#((8y^19)/(x^15))#

Hope this helps!

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