How do you divide $\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }$ ?

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Answer 1 · 2017-06-22T01:50:31

Here is the answer: $((8y^19)/(x^15))$

First of all, expand the exponents: $((4x^8y^5)/(8x^3y^3))/((x^24y^15)/(16x^4y^32))$

Next, switch the sign and find the reciprocal of the fraction: $((4x^8y^5)/(8x^3y^3))*((16x^4y^32)/(x^24y^15))$

Multiply: $((64x^12y^37)/(8x^27y^18))$

Cancel terms to get the final answer: $((8y^19)/(x^15))$

Hope this helps!

How do you divide \frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }?