How do you divide $\frac{4 x^{8} y^{5}}{{(2 x y)}^{3}} \div \frac{{(x^{8} y^{5})}^{3}}{{(2 x y^{8})}^{4}}$ $\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }$ ?

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How do you divide $\frac{4 x^{8} y^{5}}{{(2 x y)}^{3}} \div \frac{{(x^{8} y^{5})}^{3}}{{(2 x y^{8})}^{4}}$ $\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }$ ?

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Answer 1 · 2017-06-22T01:50:31

Here is the answer: $(\frac{8 y^{19}}{x^{15}})$ $((8y^19)/(x^15))$

Explanation:

First of all, expand the exponents: $\frac{\frac{4 x^{8} y^{5}}{8 x^{3} y^{3}}}{\frac{x^{24} y^{15}}{16 x^{4} y^{32}}}$ $((4x^8y^5)/(8x^3y^3))/((x^24y^15)/(16x^4y^32))$

Next, switch the sign and find the reciprocal of the fraction: $(\frac{4 x^{8} y^{5}}{8 x^{3} y^{3}}) \cdot (\frac{16 x^{4} y^{32}}{x^{24} y^{15}})$ $((4x^8y^5)/(8x^3y^3))*((16x^4y^32)/(x^24y^15))$

Multiply: $(\frac{64 x^{12} y^{37}}{8 x^{27} y^{18}})$ $((64x^12y^37)/(8x^27y^18))$

Cancel terms to get the final answer: $(\frac{8 y^{19}}{x^{15}})$ $((8y^19)/(x^15))$

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How do you divide $\frac{4 x^{8} y^{5}}{{(2 x y)}^{3}} \div \frac{{(x^{8} y^{5})}^{3}}{{(2 x y^{8})}^{4}}$ $\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }$ ?

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Explanation:

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How do you divide \frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }4x8y5(2xy)3÷(x8y5)3(2xy8)4\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }?

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Explanation:

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How do you divide $\frac{4 x^{8} y^{5}}{{(2 x y)}^{3}} \div \frac{{(x^{8} y^{5})}^{3}}{{(2 x y^{8})}^{4}}$ $\frac { 4x ^ { 8} y ^ { 5} } { ( 2x y ) ^ { 3} } \div \frac { ( x ^ { 8} y ^ { 5} ) ^ { 3} } { ( 2x y ^ { 8} ) ^ { 4} }$ ?