How do you solve $\frac{3}{2 x} + \frac{1}{5} = 0$ $\frac { 3} { 2x } + \frac { 1} { 5} = 0$ ?

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Answer 1 · 2017-06-22T01:30:48

answer: $- \frac{15}{2}$ $-15/2$

Here are the steps:

$\frac{3}{2 x} + \frac{1}{5} = 0$ $3/(2x)+1/5=0$

Subtract $\frac{1}{5}$ $1/5$ from both sides.

$\frac{3}{2 x} = - \frac{1}{5}$ $3/(2x)=-1/5$

Multiply both sides by $- 2 x$ $-2x$ .

$3 = \frac{- 2 x}{5}$ $3=(-2x)/5$

Multiply both sides by $5$ $5$ .

$15 = - 2 x$ $15=-2x$

Divide both sides by $2$ $2$ .

$x = - \frac{15}{2}$ $x=-15/2$

Hope this helps!

How do you solve 32x+15=0\frac { 3} { 2x } + \frac { 1} { 5} = 0?