Question #ae9c9
1 Answer
Jun 21, 2017
Explanation:
#"the equation of a circle in standard form is "#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where " (a,b)" are the coordinates of the centre and "#
#"r is the radius"#
#"since the centre is " (-4,6)" and is tangent to x-axis"#
#"then the centre is 6 units from the x-axis"#
#rArr"radius r "= 6#
#(x-(-4))^2+(y-6)^2=6^2#
#rArr(x+4)^2+(y-6)^2=36larrcolor(red)" equation of circle"# graph{y^2-12y+x^2+8x+16=0 [-10, 10, -5, 5]}