How do you simplify ${(a^{4} b)}^{2}$ $(a ^ { 4} b ) ^ { 2}$ ?

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Answer 1 · 2017-06-21T05:41:55

$a^{8} b^{2}$ $a^8b^2$

Given -

${(a^{4} b)}^{2}$ $(a^4b)^2$

${(a^{4})}^{2} {(b)}^{2}$ $(a^4)^2(b)^2$

$a^{8} b^{2}$ $a^8b^2$

Answer 2 · 2017-06-21T05:42:00

$a^{8} \cdot b^{2}$ $a^8*b^2$

${(a^{4} \cdot b)}^{2}$ $(a^4*b)^2$

To solve this, you distribute the exponent to both terms.

$a^{4 \cdot 2} \cdot b^{2}$ $a^(4*2) * b^2$

Simplify the exponents.

Answer: $a^{8} \cdot b^{2}$ $a^8*b^2$

Answer 3 · 2017-06-21T05:43:16

${(a^{4} b)}^{2} = a^{8} b^{2}$ $(a^4b)^2=color(blue)(a^8b^2$

Simplify:

${(a^{4} b)}^{2}$ $(a^4b)^2$

Apply the power rule of exponents: ${(a^{m})}^{n} = a^{m \cdot n}$ $(a^m)^n=a^(m*n)$ .

$a^{4 \cdot 2} b^{1 \cdot 2}$ $a^(4*2)b^(1*2)$

Simplify.

$a^{8} b^{2}$ $a^8b^2$

How do you simplify (a4b)2(a ^ { 4} b ) ^ { 2}?