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If #h(x) = x-7 and g(x) = x^2#, what is #(g*h)(5)#?

1 Answer

Konstantinos Michailidis

Jun 21, 2017

Because the domain of h and g is the set of real numbers their product can be defined.

Hence

#h(x)*g(x)=(h*g)(x)=(x-7)*x^2#

Hence

#(h*g)(5)=(5-7)*5^2=-50#

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