How do you calculate #(2+3i)+(-3-2i)#?

1 Answer
Jun 20, 2017

#-1+i#

Explanation:

#(2+3i)+(-3-2i)#

Get rid of the parentheses using the Associative Property of Addition. Basically you don't need parentheses when adding because you can add numbers in any order and get the same answer.

#2+3i-3-2i#

Combine like terms by adding the constants together and the imaginary numbers together. Add imaginary numbers by adding their coefficients together. Treat #i# like a variable.

#-1+i#

[Remember to write complex numbers in the form #(a+bi)# where #a=#real number, #b=#coefficient of imaginary number, and #i# is the imaginary number.]

Answer: #-1+i#