How do you simplify $r^ { 2} \cdot r ^ { - 4} \cdot r ^ { 3}$ ?

Question

1337 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-18T22:45:32

Add the Exponents up

Let's say r=5
$r=5$
$r^2 * r^-4 * r^3=5$
If you the exponents up
$2 + (-4) + 3 = 1$
It equals one so
$5^1 = 5$

Answer 2 · 2017-06-19T02:00:51

$r^2xxr^(-4)xxr^3=r^(2-4+3)=r^(1)=r$

We can use the rule:

$x^axxx^b=x^(a+b)$

and so we have

$r^2xxr^(-4)xxr^3=r^(2-4+3)=r^(1)=r$

How do you simplify r^ { 2} \cdot r ^ { - 4} \cdot r ^ { 3}r^ { 2} \cdot r ^ { - 4} \cdot r ^ { 3}?