How do you simplify #r^ { 2} \cdot r ^ { - 4} \cdot r ^ { 3}#?

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Answer 1 · 2017-06-18T22:45:32

Add the Exponents up

Let's say r=5
#r=5#
#r^2 * r^-4 * r^3=5#
If you the exponents up
#2 + (-4) + 3 = 1#
It equals one so
#5^1 = 5#

Answer 2 · 2017-06-19T02:00:51

#r^2xxr^(-4)xxr^3=r^(2-4+3)=r^(1)=r#

We can use the rule:

#x^axxx^b=x^(a+b)#

and so we have

#r^2xxr^(-4)xxr^3=r^(2-4+3)=r^(1)=r#