How do you simplify log2(x6y78)?

2 Answers
Jun 15, 2017

The expression equals 6log2x+7log2y3

Explanation:

Use the following laws of logarithms to simplify the above problem

loga(nm)=logan+logam
loga(nm)=loganlogam
log(an)=nloga

Now apply them:

=log2(x6y7)log28

=log2x6+log2y73

=6log2x+7log2y3

Hopefully this helps!

Jun 15, 2017

log2(x6)+log2(y7)3

Explanation:

Use log properties:
Product Rule:
logx+logy=logxy

Quotient Rule:
logxlogy=log(xy)

Split the fraction into two separate logs using the Quotient Rule.
log2(x6y78)
log2(x6y7)log2(8)

Split (x6y7) into two separate logs using the Product Rule.
log2(x6y7)log2(8)
log2(x6)+log2(y7)log2(8)

Simplify log2(8).
log2(x6)+log2(y7)log2(8)
log2(x6)+log2(y7)3

log2(x6)+log2(y7)3 is your simplified expression.