How do you solve $- \frac{242}{21} = - \frac{9}{4} x + \frac{1}{3} - 8$ $-\frac { 242} { 21} = - \frac { 9} { 4} x + \frac { 1} { 3} - 8$ ?

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Answer 1 · 2017-06-12T07:00:59

$x = 1 \frac{5}{7}$ $x = 1 5/7$

$-242/21 color(red)(+ 8) = -9/4 x + 1/3 color(red)(cancel(color(black)(- 8) color(red)( + 8)$

$-11 11/21 + 8 = -9/4 x + 1/3$

$-3 11/21 -1/3 = -9/4 x color(red)(cancel( color(black)(+ 1/3) color(red)(-1/3)$

$-3 11/21 -7/21 = -9/4 x$

$-3 18/21= -9/4 x$

$-3 6/7 color(red)(÷ -9/4)= color(red)(cancel(color(black)(-9/4) color(red)(÷ -9/4)) x$

$x = -3 6/7 ÷ -9/4$

$x = -3 6/7 xx -4/9$

$color(blue)(x = 1 5/7$

We can now substitute $1 5/7$ for $x$ in the equation to prove our answer.

$-242/21 = -9/4 x + 1/3 - 8$

$-242/21 = -9/4 xx 1 5/7 + 1/3 - 8$

$-242/21 = -3 6/7 + 1/3 - 8$

$-242/21 = -3 11/21 - 8$

$-242/21 = -11 11/21$

$-242/21 = -242/21$

How do you solve -\frac { 242} { 21} = - \frac { 9} { 4} x + \frac { 1} { 3} - 8−24221=−94x+13−8-\frac { 242} { 21} = - \frac { 9} { 4} x + \frac { 1} { 3} - 8?