What is the area of a rectangle that has a base of $5$ $m$ and a height of $(4a +b)$ $m$ ?

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Answer 1 · 2017-06-11T21:54:58

If m is a variable, the area is $4am^2+bm^2$ units squared, but if m means meters, then the area is $20a+5b$ meters squared.

We should begin by finding the simplest version of the height. To do this, we distribute the m, to find:

$4am+bm$ is the height.

Next, we find the area by multiplying the base by the height. This is how it is set up:

$(4am+bm)*m$

We distribute m to find:

$4am^2+bm^2$ units squared, and this is our final answer.

^that explanation was done with m being a variable, but i realize now that you might have meant meters. If so, this is the explanation:

The area of a rectangle is base*height. So, we multiply 5 meters by (4a+b) meters.

$(4a+b)*5$
$20a+5b$ meters squared would be your final answer in this case.

What is the area of a rectangle that has a base of 55 mm and a height of (4a +b)(4a +b) mm?