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How do you multiply # (x^(3/2) + 2/sqrt3)^2#?

1 Answer

Jun 9, 2017

See a solution process below:

Explanation:

This is a special form of quadratic:

#(a + b)^2 = a^2 + 2ab + b^2#

Substituting #x^(3/2)# for #a# and #2/sqrt(3)# for #b# gives:

#(x^(3/2) + b)^2 = (x^(3/2))^2 + (2 * x^(3/2) * 2/sqrt(3)) + (2/sqrt(3))^2 =#

#x^3 + (4x^(3/2))/sqrt(3) + 4/3#

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