how do you solve $3 (4 x - 15) = 19$ $3( 4x - 15) = 19$ ?

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Answer 1 · 2017-06-08T13:56:08

$x = \frac{16}{3}$ $x=16/3$

$3 (4 x - 15) = 19$ $3(4x-15)=19$

Expand the parenthesis on the left side of the equation by multiplying all terms inside of the parenthesis by 3.

$12 x - 45 = 19$ $12x-45=19$

Add 45 to both sides of the equation.

$12 x = 64$ $12x=64$

Divide both sides of the equation by 12.

$x = \frac{16}{3}$ $x=16/3$

how do you solve 3( 4x - 15) = 193(4x−15)=193( 4x - 15) = 19?