How do you subtract $\frac { x ^ { 2} - 10x } { x ^ { 2} - 11x - 12} - \frac { 24} { x ^ { 2} - 11x - 12}$ ?

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Answer 1 · 2017-06-07T05:45:46

It's $(x+2)/(x+1)$ .

Let's start with the original problem:

$(x^2-10x)/(x^2-11x-12)-(24)/(x^2-11x-12)$

Noting that the two fractions have common denominators, we can simplify the expression as so:

$(x^2-10x-24)/(x^2-11x-12)$

Then, we can factor both the numerator and the denominator into a $(x+a)(x+b)$ format:

$((x+2)(x-12))/((x+1)(x-12))$

Then, we cancel the $x-12$ s and finish the problem with the final answer:

$(x+2)/(x+1)$

How do you subtract \frac { x ^ { 2} - 10x } { x ^ { 2} - 11x - 12} - \frac { 24} { x ^ { 2} - 11x - 12}\frac { x ^ { 2} - 10x } { x ^ { 2} - 11x - 12} - \frac { 24} { x ^ { 2} - 11x - 12}?