The specific heat of iron is 0.46 J/gC. How many joules will it take to make the temperature of a 150 g bar go up from 25 C to 60 C?

1 Answer

2415 J

Explanation:

We know, Heat Absorbed or Evolved by a substance = mass * specific heat capacity * change in temperature.

Here,

Mass (m) = 150g(m)=150g
Specific heat capacity (c) = (0.46J)/(gK)(c)=0.46JgK
Initial Temperature = 25^@C25C
Final Temperature = 60^@C60C
DeltaT=60-25=35^@C=35K

Therefore, total heat supplied = DeltaE = mcDeltaT
= 150 * 0.46 * 35 J
= 2415 J