How do you solve the system of equations #6x-7y = 8# and #9x-5y =1#?

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Answer 1 · 2017-06-03T12:07:31

#x= -1, y=-2#

Your question ;

#6x-7y=8#
#9x-5y=1#

Let's solve by eliminating #x#. Since 18 is the lowest common multiple , let's multiply the first equation by 3 and the second by -2.

#18x-21y=24#
#-18x+10y=-2#

Add the two equations.

#-11y=22#

Divide by -11 to isolate #y#.

#y=-2#

Substitute #y=-2# into either of the 2 equations, I'll just use the second one.

#9x+10=1#

#9x=-9#

#x=-1#