How do you find the area of the lateral faces of the right triangular prism with altitude of 5 cm and base edges of length 3 cm, 4 cm, and 5 cm?

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Answer 1 · 2017-05-30T06:42:36

The total lateral area for the Triangular prism is $60 {cm}^{2}$ $60"cm"^2$

$A = l \times w$ $A = l xx w$

$Lateral Area = l_{1} \times w_{1} + l_{2} \times w_{2} + l_{3} \times w_{3}$ $"Lateral Area" = l_1 xx w_1 + l_2 xx w_2 + l_3 xx w_3$

$Side 1 = 5 \times 3$ $"Side 1" = 5 xx 3$

$Side 1 = 15 {cm}^{2}$ $color(blue)("Side 1" = 15"cm"^2$

$Side 2 = 5 \times 4$ $"Side 2" = 5 xx 4$

$Side 2 = 20 {cm}^{2}$ $color(blue)("Side 2" = 20"cm"^2$

$Side 3 = 5 \times 5$ $"Side 3" = 5 xx 5$

$Side 3 = 25 {cm}^{2}$ $color(blue)("Side 3" = 25"cm"^2$

$Lateral Area = 5 \times 3 + 5 \times 4 + 5 \times 5$ $"Lateral Area" = 5 xx 3 + 5 xx 4 + 5 xx 5$

$Lateral Area = 15 + 20 + 25$ $"Lateral Area" = 15 + 20 + 25$

$Lateral Area = 60 {cm}^{2}$ $color(red)("Lateral Area" = 60"cm"^2$