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Question #c25c8

1 Answer

May 29, 2017

In it's lowest form, the expression equals $\frac{3 (x + 3)}{2 x + 1}$ $(3(x+3))/(2x+1)$ , or $\frac{3 x + 9}{2 x + 1}$ $(3x+9)/(2x+1)$

Explanation:

First off, we should factor $(3x²-27)/(2x²-5x-3)$ , and this produces:

$(3(x-3)(x+3))/((2x+1)(x-3))$

Now cancel out the term $(x-3)$ from the numerator and denominator:

$(3cancel((x-3))(x+3))/((2x+1)cancel((x-3)))$

$(3(x+3))/(2x+1)$

From here you can distribute the $3$ to form $3x+9$ or leave it as that.

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