Question #c25c8

1 Answer
Krishna V.
May 29, 2017

In it's lowest form, the expression equals (3(x+3))/(2x+1), or (3x+9)/(2x+1)

Explanation:

First off, we should factor (3x²-27)/(2x²-5x-3), and this produces:

(3(x-3)(x+3))/((2x+1)(x-3))

Now cancel out the term (x-3) from the numerator and denominator:

(3cancel((x-3))(x+3))/((2x+1)cancel((x-3)))

(3(x+3))/(2x+1)

From here you can distribute the 3 to form 3x+9 or leave it as that.

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