How do you solve $3 - x = \frac{2}{x}$ $3-x=2/x$ ?

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How do you solve $3 - x = \frac{2}{x}$ $3-x=2/x$ ?

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Answer 1 · 2017-05-28T19:28:44

$x = 2 or 1$ $x=2 or 1$

Explanation:

By multiplying $x$ $x$ on both sides of the equation,
$(3 - x) x = \frac{2}{x} \cdot x$ $(3-x)x=2/x*x$
$3 x - x^{2} = 2$ $3x-x^2=2$
$x^{2} - 3 x + 2 = 0$ $x^2-3x+2=0$
$(x - 2) (x - 1) = 0$ $(x-2)(x-1)=0$
$x = 2 or 1$ $x=2 or 1$

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How do you solve $3 - x = \frac{2}{x}$ $3-x=2/x$ ?

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How do you solve 3-x=2/x3−x=2x3-x=2/x?

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How do you solve $3 - x = \frac{2}{x}$ $3-x=2/x$ ?