What is $(- 4 a^{2}) {(2 a^{- 3})}^{- 4}$ $(-4a^2)(2a^-3)^-4$ ?

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What is $(- 4 a^{2}) {(2 a^{- 3})}^{- 4}$ $(-4a^2)(2a^-3)^-4$ ?

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Answer 1 · 2017-05-28T19:25:42

$- \frac{a^{14}}{4}$ $-a^14/4$

Explanation:

$(- 4 a^{2}) {(2 a^{- 3})}^{- 4}$ $(-4a^2)(2a^-3)^-4$

$= \frac{- 4 a^{2}}{{(\frac{2}{a^{3}})}^{4}}$ $=(-4a^2)/(2/a^3)^4$
$= \frac{(- 4 a^{2}) {(a^{3})}^{4}}{2^{4}}$ $=((-4a^2)(a^3)^4)/2^4$
$= - \frac{a^{14}}{4}$ $=-a^14/4$

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