Question #8537b

Question

Question #8537b

1 Answer

Impact of this question

1041 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-27T23:11:05

-0.75

Explanation:

By considering the trigonometric identity,

${sin}^{2} (x) + {cos}^{2} (x) = 1$ $sin^2(x)+cos^2(x)=1$
${0.6}^{2} + {cos}^{2} (x) = 1$ $0.6^2+cos^2(x)=1$
$cos (x) = \pm 0.8$ $cos(x)=+-0.8$

By considering the CAST rule, because $90 < x < 180$ $90< x < 180$ , $x$ $x$ is in quadrant II, therefore $cos (x)$ $cos(x)$ is negative, i.e. $cos (x) = - 0.8$ $cos(x)=-0.8$

By considering the CAST rule, $tan (π - x) = \frac{sin (π - x)}{cos (π - x)} = \frac{sin (x)}{- cos (x)} = - tan (x)$ $tan(pi-x)=sin(pi-x)/cos(pi-x)=sin(x)/-cos(x)=-tan(x)$

Therefore $tan (π - x) = \frac{sin (x)}{- cos (x)} = \frac{0.6}{- 0.8} = - 0.75$ $tan(pi-x)=sin(x)/-cos(x)=0.6/-0.8=-0.75$

Science

Math

Humanities

... and beyond

Question #8537b

1 Answer

Explanation:

Related questions

Impact of this question