How do you combine \frac { 3} { 2b ( 3b - 2) } - \frac { 3} { 2b }32b(3b−2)−32b into one term?

1 Answer
Justin
May 27, 2017

(9-9b)/(6b^2-4b)9−9b6b2−4b

Explanation:

3/(2b(3b-2)) - 3/(2b)32b(3b−2)−32b
= (3/(2b))(1/(3b-2)-1)=(32b)(13b−2−1)
= (3/(2b))((1-3b+2)/(3b-2))=(32b)(1−3b+23b−2)
= (3/(2b))((3-3b)/(3b-2))=(32b)(3−3b3b−2)
= (9-9b)/(6b^2-4b)=9−9b6b2−4b

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