How do you solve $- \frac{1}{2} = \frac{3}{4} x - x$ $-\frac { 1} { 2} = \frac { 3} { 4} x - x$ ?

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How do you solve $- \frac{1}{2} = \frac{3}{4} x - x$ $-\frac { 1} { 2} = \frac { 3} { 4} x - x$ ?

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Answer 1 · 2017-05-25T23:50:24

In the equation $- \frac{1}{2} = \frac{3}{4} x - x$ $-1/2 = 3/4x - x$ , $x = 2$ $x=2$ .

Explanation:

You can factor out the $x$ $x$ in $- \frac{1}{2} = \frac{3}{4} x - x$ $-1/2 = 3/4x - x$ to equal $- \frac{1}{2} = x (\frac{3}{4} - 1)$ $-1/2 = x(3/4 -1)$ .

After that, $- \frac{1}{2} = - \frac{1}{4} x$ $-1/2 = -1/4x$ after you do the math in the parentheses and you would multiply both sides by 4 to get $- 2 = - x$ $-2=-x$ .

This can be rewritten as $- x = - 2$ $-x=-2$ and you divide by -1 on both sides to get $x = 2$ $x=2$ .

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How do you solve $- \frac{1}{2} = \frac{3}{4} x - x$ $-\frac { 1} { 2} = \frac { 3} { 4} x - x$ ?

1 Answer

Explanation:

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